echo JavaScript inside PHP -

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• what difference between client-side , server-side programming? 5 answers

i using following code change button when clicked echoing javascript's document.getelemenbyid property button remains is:

while($result=mysql_fetch_array($result1))                     {                         $i=1;                         echo "                         <tr>                         <form action='student.php' method='post'>                         <td>$result[0]<input type=\"hidden\" name=\"company\" value=\"$result[0]\"></td>                         <td>                         <input type=\"checkbox\" name=\"yes\" />                         <input type=\"submit\" name=\"apply$i\" id=\"apply$i\" class=\"buttons\" style=\"border: none\" value=\"apply now!\"                                    onclick=\"return confirm('are sure want apply?');\">                            <input type=\"hidden\" name=\"apply$i\" value=\"apply$i\">                         </td>                         </form>                         </tr>                         <tr><td><input type=\"text\" id=\"ankur\"></td></tr>                         ";                         $i++;                     }                     echo "</table></center>"; 

here button id apply$i should change applied string per following code

$id=$_session['sessionid']; if(isset($_post['apply1'])) {     if(isset($_post['yes']))     {         $yes=trim(mysql_prep($_post['yes']));         $company=trim(mysql_prep($_post['company']));         $button_id=trim(mysql_prep($_post['apply1']));         if($yes=="on")         {             $query ="select `branch`,`class` `student_details` `userid`='$id'";              $temp1= mysql_query($query);             $temp2= mysql_fetch_array($temp1);             $query="insert `student_applied` values ('$id' ,'$temp2[0]' ,'$temp2[1]' ,'$company')";             //$query="update `student`.`users` set  `activated` =  '1'  `users`.`userid` =  '$student'";             $result = mysql_query($query);             confirm_query($result);             if($result)             {             echo "ok";             echo "<script language='javascript' type='text/javascript'>document.getelementbyid('apply1').innerhtml ='applied';</script>" 

does know reason?plz help

instead of settingg $i inside loop, should set outside , increment value, like

$i=1; while($result=mysql_fetch_array($result1)){     //your rest of code output content     $i++; } 

that way have different id each button, , javascript should work you.