Find position of a node using xpath -

anyone know how position of node using xpath?

say have following xml:

<a>     <b>zyx</b>     <b>wvu</b>     <b>tsr</b>     <b>qpo</b> </a> 

i can use following xpath query select third <b> node (<b>tsr</b>):

a/b[.='tsr'] 

which , want return ordinal position of node, like:

a/b[.='tsr']/position() 

(but bit more working!)

is possible?

edit: forgot mention using .net 2 it's xpath 1.0!

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update: ended using james sulak's excellent answer. interested here's implementation in c#:

int position = doc.selectnodes("a/b[.='tsr']/preceding-sibling::b").count + 1;  // check node exists if (position > 1 || doc.selectsinglenode("a/b[.='tsr']") != null) {     console.writeline("found @ position = {0}", position); } 

try:

count(a/b[.='tsr']/preceding-sibling::*)+1.