c# - Async Await In Linq .TakeWhile -

i trying convert foreach function linq function

here normal code [works fine]

    var tlist = new list<func<task<bool>>> { method1, method2 };     tlist.shuffle();      int succeed = 0;     foreach (var task in tlist)     {         var result = await task();          if(!result)             break;          succeed += 1;     }      messagebox.show(succeed == 1 ? "loading complete." : "something went wrong!"); 

and here after converted linq [giving 2 compiler errors]

    var tlist = new list<func<task<bool>>> { method1, method2 };     tlist.shuffle();      int succeed = tlist.select(async task => await task()).takewhile(result => result).count();      messagebox.show(succeed == 1 ? "loading complete." : "something went wrong!"); 

errors

• cannot convert lambda expression delegate type 'system.func,bool>' because of return types in block not implicitly convertible the
  delegate return type
• cannot implicitly convert type 'system.threading.tasks.task' 'bool'

i wonder why compiler giving messages, appreciated.

note : tried .takewhile(async result => await result) error

• the return type of async method must void, task, or task t

method1 , method2 if wanna them :

public async task<bool> method1() {     await task.delay(1000);     console.writeline("method1");     return false; }  public async task<bool> method2() {     await task.delay(1000);     console.writeline("method2");     return true; } 

this because cannot convert task<bool> bool.. compiler has instructed.

change this:

.takewhile(result => result) 

..to this:

.takewhile(result => result.result)