python - How to sort list within a list? -

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• how sort list of lists specific index of inner list? 6 answers

i want sort list based on first item such as:

fruits = \ [['mango', 6, 5, 8.0],  ['banana', 2.0, 5, 8.9, 7],  ['pineapple', 4, 6.8, 9],  ['apple', 3.9, 6, 7, 2]] 

to sorted out this:

fruits = \ [['apple', 3.9, 6, 7, 2],  ['banana', 2.0, 5, 8.9, 7],  ['mango', 6, 5, 8.0],  ['pineapple', 4, 6.8, 9]] 

i know have use sort() function don't know how use in right way produce outputs want.

what problem exactly? sort() sorts first element.

in [14]: fruits = [["mango", 6,5,8.0],          ["banana", 2.0,5,8.9,7],          ["pineapple", 4,6.8,9],          ["apple", 3.9,6,7,2]]  in [15]: fruits.sort()  in [16]: fruits out[16]:  [['apple', 3.9, 6, 7, 2],  ['banana', 2.0, 5, 8.9, 7],  ['mango', 6, 5, 8.0],  ['pineapple', 4, 6.8, 9]] 

if items classes or variables, should implement comparison methods (__ge__, __le__, __gt__, __lt__) accordingly sorting needs.

keep in mind fruits.sort() modifies list in place, if want new sorted copy, use sorted(fruits)