python - Compare two dictionaries with one key in common and form a new dictionary combining the remaining keys associated with this common key -

i have 2 dictionaries, 1 contains name , initial values of registers , other contains name , address values of same registers.

i need compare 2 dictionaries on register names [id] , take initial value of register [initvalue] dictionary 1 , address values [addrvalue] dictionary 2 , put them in new dictionary key in new dictionary becomes address rather register name.

below doing don't know how merge 2 dictionary keys.

regex = "(?p<id>\w+?)_init\s*?=.*?'h(?p<initvalue>[0-9a-fa-f]*)" x in re.findall(regex, lines):     init_list = (x.groupdict()["id"], "0x" + x.groupdict()["initvalue"])  regex = "(?p<id>\w+?)_addr\s*?=.*?'h(?p<addrvalue>[0-9a-fa-f]*)" y in re.findall(regex, lines):     addr_list = (y.groupdict()["addr_id"], "0x" + y.groupdict()["addrvalue"])  key in set(init_list['init_id'].keys()).union(addr_list['id'].keys()):     if init_list[key] == addr_list[key]         expect_by_addr = dict (addr_list['addrvalue']   # here 

make first 2 dictionaries:

dict1 = {} dict2 = {} x in range(0, 10):     dict1[x] = "initvalue{}".format(x)     y = x+3     dict2[y] = "address{}".format(y) 

combine them based on dict2 "addresses"

dict3 = {} #note because want addresses key of new dictionary #we need @ keys exist in both dict1 , dict2. key in dict2.keys():     if key in dict1:         dict3[dict2[key]] = dict1[key] 

dictionaries:

dict1 {0: 'initvalue0', 1: 'initvalue1', 2: 'initvalue2', 3: 'initvalue3', 4: 'initvalue4', 5: 'initvalue5', 6: 'initvalue6', 7: 'initvalue7', 8: 'initvalue8', 9: 'initvalue9'}  dict2 {3: 'address3', 4: 'address4', 5: 'address5', 6: 'address6', 7: 'address7', 8: 'address8', 9: 'address9', 10: 'address10', 11: 'address11', 12: 'address12'}  dict3 (combined) {'address5': 'initvalue5', 'address4': 'initvalue4', 'address7': 'initvalue7', 'address6': 'initvalue6', 'address3': 'initvalue3', 'address9': 'initvalue9', 'address8': 'initvalue8'}