PHP/SQL compare two table ID and view the name -

i making script our online game site, want compare result table tabl , view id name.

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from i've show last characteridx

now problem part, comparing 2 tables

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problm solved! alot!

try this:

$sql = 'select * '.$db_gam.'.dbo.cabal_character_table characteridx = '.$saint_owner; echo "sql= ", $sql; $query = mssql_query($sql);

this output sql command, can check if sql output , send database correct , expect be.

however, think error in fact using mssql_ , mysql_ next eachother:

make this:

$query = mssql_query('select * '.$db_gam.'.dbo.cabal_character_table characteridx = '.$saint_owner);

to start.

Brande