Modify list with python by index[0] value -


i have browsed similar threads lot, maybe due lack of knowledge in python, haven't found working solution in problem.

this part of code:

for line in splitline:     if("fam" in line):         if("nk" in line or "v" in line):             normaali = line.split()             normaalilista.append(normaali)             both.append(normaali)         if("tk" in line):             tumor = line.split()             tuumorilista.append(tumor)             both.append(tumor)

the output of "both" looks atm:

['fam_c828_1', '12-0799nk', '100'] ['fam_c828_1', '12-0800tk', '100'] ['fam_s56_1', '12-0801tk', '100'] ['fam_s134_1', '12-0802nk', '100'] ['fam_s146_1', '12-0803tk', '100']

i reserve lines / cells same index[0] value. in case:

['fam_c828_1', '12-0799nk', '100'] ['fam_c828_1', '12-0800tk', '100']

and rest removed list.

thanks in advance

you use itertools.groupby:

>>> itertools import groupby >>> groups = groupby(both, lambda x: x[0]) # group `both` zeroth index of members >>> group = next(groups) # first group in groups >>> group ('fam_c828_1', <itertools._grouper object @ 0x10f065d10>) >>> list(group[1]) # cast group iterable list display purposes [['fam_c828_1', '12-0799nk', '100'], ['fam_c828_1', '12-0800tk', '100']]

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