mysql - select name from php query and refresh seprate query on same page. -


i have used first bit of ajax search mysql database. persons name add href result (which have) , post seprate page show the relevant details, eg address, grade , location. wondering if possible staying on same page. have far. ( , yes css moving seprate page)

<?php if(!strlen(trim($_session['unique_id']))) {  header("location:roster.php");  exit(); } ?> <title>search roster</title>     <style>         body {             font-family: "lucida grande", verdana, arial, sans-serif;             font-size: 12px;         }         #results {             color: #fff;             background: #414141;             width: 180px;             max-height: 200px;             padding-left: 4px;             border: 1px solid #000;             overflow-y: scroll;             overflow-x: hidden;         }         { color: #fff; display: block; }         a:hover { background: #666666; }  </style>     keyword search:     <form id="searchform" method="post" onsubmit="return false;"><input autocomplete="off" id="searchbox" name="searchq" onkeyup="sendrequest()" type="textbox">     </form><div id="show_results"></div><script src="config/prototype.js" type="text/javascript"> </script>     <script> function sendrequest() {new ajax.updater('show_results', 'pages/login/search.php', { method: 'post', parameters: $('searchform').serialize() });         }  </script> <?php include("pages/include/footer.php"); ?>

and search.php page

<?php $host="****"; // host name  $sqlusername="****"; // mysql username  $sqlpassword="****"; // mysql password  $db_name="****"; // database name  $tbl_name="****"; // table name mysql_connect("$host", "$sqlusername", "$sqlpassword")or die("cannot connect");  mysql_select_db("$db_name")or die("cannot select db"); $searchq = $_post['searchq']; if(empty($searchq)) { echo ""; } else { echo "<div id='results'-->";   //this query searches name field whatever input is.  $sql = "select * user employee '%$searchq%' or staff '%$searchq%'";          echo "<table border='3'> <tr> </tr>"; $result = mysql_query($sql); while($row = mysql_fetch_assoc($result)) {     $name = $row['employeename'];     $id=$row['unique_id'];     echo "<a href=anotherpage.php?item=".$id."</a>";     echo "$name";               echo "</br>";       }                echo "</div>"; } ?>

you have did mistake in following line of code in "search.php". verify other line of code. 

echo "<a href=anotherpage.php?item=".$id."</a>";   echo "$name";

above code should follows : 

 echo "<a href=anotherpage.php?item=".$id.">".$name."</a>";


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