java - Regular expression on a string -

i have string below

string phone = (123) 456-7890

now program verify if input same pattern string 'phone'

i did following

if(phone.contains("([0-9][0-9][0-9]) [0-9][0-9][0-9]-[0-9][0-9][0-9][0-9]")) {     //display pass } else {     //display fail }

it didn't work. tried other combinations too. nothing worked.

question : 1. how can achieve without using 'pattern' above? 2. how pattern. tried pattern below

pattern pattern = pattern.compile("(\d+)"); matcher match = pattern.matcher(phone);

if (match.find()) {    //displaypass }

string#matches checks if string matches pattern:

if (phone.matches("\\(\\d{3}\\) \\d{3}-\\d{4}")) {     //displaypass }

the pattern regular expression. therefor had escape round brackets, have special meaning in regex (they denote capturing groups).

contains() checks if string contains substring passed it.

Brande