excel - How to check in another table if an agency is in a specific region -


there many travel agencies each code of 3 characters in column. want know if travel agency in atlantic canada. can list of codes corresponding travel agencies in atlantic canada database , put them in single column in worksheet in same excel file, i'm not sure of exact syntax writing if ...lookup or if there better excel formula/technique.

if codes in d2:d68 in example, want column e (e2:e68) if value in column d corresponds 1 of lengthy list of codes. column e display yes/no or true/false or similar.

i've been looking @ various tutorials. don't want anything, want yes/no or true/false three-character code 1 of, or not 1 of, many atlantic canada codes.

suggestions?

if reference list in in columna of sheet 2, try =vlookup(d2,sheet2!a:a,1,false) in e2 copied down required. adapted show true/false identification purposes code repeat seems adequate. false accept match when exact (true allow approximate matches - ie similar not correct). ones not match display#name?

edit

for t/f results
=iferror(if(match(d1,'atlantic canada codes'!a:a,0)>0,"true","false"),"false")
should work (though less inelegant seems possible!)

edit re apparent inconsistency in formulae results mentioned in comment

  • =trim() (worksheet) , trim (vba) behave differently.
  • =match , =v / h lookup() may behave differently according whether exact or otherwise.
  • a space character may ‘normal’ (7-bit ascii code 32) or non-breaking (&nbsp code 160).

rather cover these combinations, simplified (so far complete) explanation ‘extra’ spaces problem, trailing ones, apply =trim() both data looked (ie key) , @ least part of array (the keys) relate required results.

it possible apparent inconsistency mentioned in comment arose because something+space not matching something , in removing +space something+space same applied somethingelse+space. hence before =trim() somethingesle+space matching somethingelse+space after somethingelse no longer matching somethingelse+space.

that problem switched 'surplus' spaces in 1 list 'surplus' spaces in other. either have these spaces in neither, or if must, in both.

ref:


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