c++ - Swap elements in array to reverse an array -

i got assignment reverse dynamic array in c++. far, logic, thinking of loop thru array reverse it. , here comes code :

int main () {     const int size = 10;     int num_array[size];      srand (time(null));      (int count = 0; count< sizeof(num_array)/sizeof(num_array[0]) ; count++){         /* generate secret number between 1 , 100: */         num_array[count] = rand() % 100 + 1;         cout << num_array[count] << " " ;     }      reverse(num_array[size],size);      cout << endl;      system("pause");     return 0; }  void reverse(int num_array[], int size) {     (int count =0; count< sizeof(num_array)/sizeof(num_array[0]); count++){         cout << num_array[sizeof(num_array)/sizeof(num_array[0])-1-count] << " " ;     }      return; } 

somehow think logic there code doesn't works, there's error. however, teacher told me isn't way question wants. , here question :

    write function reverse reverses sequence of elements in array. example, if reverse called array containing 1 4 9 16 9 7 4 9 11, array changed 11 9 4 7 9 16 9 4 1. 

so far, told in reverse method, need swap array element. here's question how swap array element array entered reversed?

thanks in advance.

updated portion

    int main () { const int size = 10; int num_array[size];  srand (time(null));  (int count = 0; count< size ; count++){     /* generate secret number between 1 , 100: */     num_array[count] = rand() % 100 + 1;     cout << num_array[count] << " " ; }  reverse(num_array,size);  cout << endl;  system("pause"); return 0; 

}

void reverse(int num_array[], const int& size) { (int count =0; count< size/2; count++){     int first = num_array[0];     int last = num_array[count-1];     int temp = first;     first = last;     last = temp; } 

}

you reverse function should this:

void reverse(int* array, const size_t size) {     (size_t = 0; < size / 2; i++)     {         // stuff...     } } 

and call like:

reverse(num_array, size);