c++ - Calling overloaded operator function from struct pointer -

i have following struct in c++

struct jam {     void operator()()     {         cout << "test";     } };

and able call overloaded function so:

jam j; j();

but wondering proper way call function pointer same struct. example if have:

jam *j = new jam; j->();

i receive errors telling me needs function name. possible? thanks!

the easiest , clearest way dereference pointer:

(*j)();

alternatively, can use -> syntax function's name (which operator()):

j->operator()();

Brande