jquery - Looping and Chaining Ajax Calls using deferred -


i've seen many questions nothing seems give right answer case. i've seen answers uses .pipe i'm looking answer uses .then.

okay. need 3 ajax calls, lets poll application allows multiple accounts. processes need done account can vote following.

  1. login
  2. select option/s
  3. submit
  4. logout(just clearing cookies, no need post).

let's have 2 accounts:

var accts = [{user: "acct1", pswd: "1234"},{user: "acct2", pswd: "4321"}];

now need loop through accounts using jquery's $.each

$.each(accts, function(key,value){  });

i learned using $.deferred can perfectly, correct implementation.

what want is

--------loop1-------- login select vote --------loop2-------- login select vote done!.

but happens (when try console.log on happening) done! login(2) select(2) vote(2)

so here code:

$.each(data, function(k, v) {     promise.then(function() {         return $.post(loginurl, {user: v.username, passwrd: v.password});     }).then(function(html) {         if (data > 0) {             console.log('logged in!');             return $.post(pollurl + 'select.php', {id: 143});         } else {             console.log('login failed.');             return false;         }     }).then(function(data) {         if (data === 'selected') {             console.log('already have selection.');             return false;         } else {             return $.post(pollurl + 'submit.php');         }     }).then(function(data){          if(data > 1) {              console.log('successfully voted.');          } else {            // if possible return login?          }     }); });  promise.done(function() {     console.log('all done. logged out.'); });

what doing wrong?.

ah, similar process struggled while. solution use .apply on jquery's .when process "unknown" number of ajax calls , resolve them all.

this isn't precisely need given situation, might give ideas how attack problem. tried state process in context of you're trying do, 

var ajaxargs = [{id: 1, password: "qwerty"}, {id: 2, password: "zxcvb"}];  function dologin(id, pass) {   return $.post("ws/path/here", {id: id, pass: pass}); }  var logins = $.when.apply(null, ajaxargs.map(function(argset) {    return dologin(argset.id, argset.password);  });  logins.done(function(){     var logins = [].concat(arguments);     logins.foreach(function(login) {        //do vote        //do logout     }); });

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